Diketahui fungsi f(x)=5x-7 dan g(x)=3x+2 per 3-2x, x tidak sama dengan 3/2. Nilai dari (f bundaran g)(-1) adalah...

Mapel : Matematika

Kelas : 10

Bab : Fungsi Komposisi

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f(x) = 5x - 7

g(x) = 3x + 2/3 - 2x

Ditanya → (f o g)(-1)

Jawaban :

(f o g) (x) = f(3x + 2)/(3 - 2x)

(f o g) (x) = [5(3x + 2)/(3-2x)] - 7

(f o g) (x) = [(15x + 10)/(3 - 2x)] - 7

(f o g) (x) = [(15x + 10)/(3 - 2x)] - [7(3-2x) /(3-2x)]

(f o g) (x) = [(15x + 10)/(3-2x)] - (21 - 14x) /(3-2x)

(f o g) (x) = (29x - 11)/(3 - 2x)

Maka fungsi (f o g) (-1) adalah :


= [(29(-1) - 11)/(3 - 2(-1)]

= [-40/5]

= -8 ✔