Δ=111 km s=05.45'.55 p=...?
Geografi
Adimassaputra
Pertanyaan
Δ=111 km
s=05.45'.55"
p=...?
s=05.45'.55"
p=...?
1 Jawaban
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1. Jawaban windidn
111km = 1°
sehingga
p = 05°.45'.55" -1°
p = 04°.45'.55"