jika 27log5 = p , maka 25log3 + 243log5 adalah

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

²⁷log 5 = p
^(3³)log 5 = p
(1/3) . ³log 5 = p
³log 5 = 3p

²⁵log 3 + ²⁴³log 5
= ^(5²)log 3 + ^(3⁵)log 5
= (1/2) . ⁵log 3 + (1/5) . ³log 5
= (1/2) . 1/(3p) + (1/5) . 3p
= 1/(6p) + 3p/5
= (5 + 18p²)/(30p)