tentukan persamaan garis lurus yg melalui titik (-2,7) dan tegak lurus garis 2x-3y+4 =0

Kelas 8 Matematika
Bab Persamaan Garis

ax + by + c = 0, tegak lurus, (p, q)
bx - ay - (bp - aq) = 0

2x - 3y + 4 = 0, tegak lurus, (-2, 7)
-3x - 2y - (-3 . (-2) - 2 . 7) = 0
-3x - 2y - (6 - 14) = 0
-3x - 2y + 8 = 0
3x + 2y - 8 = 0

ax + by + c = 0, tegak lurus ,(p, q)
bx - ay - (bp - aq) = 0

2x - 3y + 4 = 0, tegak lurus, (-2, 7)
-3x - 2y - (-3 ×(-2) - 2×7) =0
-3x - 2y - (6 - 14) = 0
-3x - 2y + 8 = 0
3x + 2y - 8 =0