Matematika

Pertanyaan

-sin 45°+cos 60°-tan 45°

1 Jawaban

  • -sin 45° = - √2/2

    cos 60° = ½

    -tan 45° = -1

    -sin 45°+cos 60°-tan 45°

    = -√2/2 +½ - 1
    = -√2/2 + ½ - 2/2
    = -√2/2 -½

    √2-1
    = ---------
    2

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