Jika(x)=x+3/2-6x x#1/3

f(x) invers ?
[tex] \frac{y}{1} = \frac{x + 3}{2 - 6x} \\ 2y - 6xy = x + 3 \\ - x - 6xy = 3 - 2y \\ ( - 1 - 6y)x = 3 - 2y \\ x = \frac{3 - 2y}{ - 1 - 6y } [/tex]
[tex]finvers(x) = \frac{3 - 2x}{ - 1 - 6x} [/tex]