tolong di bantu buat besok

[tex]1. \: \frac{3 - {(3x - 3)}^{ \frac{1}{2} } }{ {x}^{2} + x - 20} = \frac{ - \frac{1}{2} {(3x - 3)}^{ - \frac{1}{2}}.3 }{2x + 1} = \frac{ - \frac{3}{2}. {9}^{ - \frac{1}{2} } }{9} = \frac{ - \frac{1}{2} }{9} = - \frac{1}{18} [/tex]
no.2 sama caranya dengan no.1 ( lakukan operasi turunan dulu)

no 1
         3 - (3x - 3)¹/²              -1/2. 3(3x - 3)⁻¹/²
lim    -----------------  =  lim   ---------------------
ˣ →⁴   x² + x - 20         ₓ→₄        2x + 1
                         
                                    -3/2 (3(4)- 3)⁻¹/²
                                = ------------------------
                                          2(4) + 1

                                    -3/2 (9)⁻¹/²
                                = ---------------
                                          9
                                   
                                = - 1/2 x 1/9
                                = - 1/18
no 2
              x² - 16                                   2x
lim  ---------------------   =  lim   ------------------------
ₓ→₄   1 - (x - 3)¹/²           ₓ→₄      - 1/2 (x - 3)⁻¹/²

                                              2(4)
                                   = --------------------
                                       - 1/2 (4 - 3)⁻¹/²
 
                                                8
                                   = --------------------
                                              - 1/2
                                   =  8 x (-2)
                                   = - 16