Koordinat titik fokus parabola y2(kuadrat) + 6y -2x + 11

y² + 6y -2x + 11 = 0
y²+6y = 2x - 11
(y+3)²-9 = 2x-11
(y+3)² = 2x - 11 + 9
(y+3)² = 2x - 2
(y+3)² = 2(x - 1)

4p = 2
 p = 1/2
fokus (1+1/2,-3) = (3/2 , -3)