Tolong ya,besok di kumpulin

5. diket : keliling lingkaran = 88
ditanya :
a. diameter lingkaran
b. jari jari lingkaran
c. luas lingkaran
Jawab :
K lingkaran = π d
88 = π × d
d = 88: π
d = 28
r = 1/2× d
r = 1/2 × 28
r = 14
L = 2 πr kuadrat
L = 2 × 22/7 × 14 × 14
L = 1232 cm persegi

6.diket = r = 10 cm
sudut AOB = 60°
ditanya = busur AB
jawab =
panjang busur = besar sudut / 360° × keliling lingkaran
P busur = 60° /360° × (2πr)
P busur = 1/60° × (2 × 3,14 × 10)
P busur = 1/60 × 62,8
P busur = 1,04