diketahui f(x-2)= x^2+3x dan g (x)= 4x + 1. rumus fungsi (f•g)(x)=

misal:
x-2=a
x=a+2

f(x-2) =x²+3x
f(x)=(a+2)²+3(a+2)
f(x)=a²+4a+4+3a+6
f(x)=a²+7a+10

(f•g)(x) =f(g(x))
f(4x+1)=a²+7a+10
=(4x+1)²+7(4x+1)+10
=16x²+8x+1+28x+7+10
=16x²+36x+18