Diketahui 4 log x = a dan pangkat 2log y = b maka x log y = ?

[tex] log_{4}(x) = a \: = > x = {4}^{a} \\ log_{2}(y) = b \: = > y = {2}^{b} [/tex]
[tex] log_{x}(y) = log_{ {4}^{a} }( {2}^{b} ) \\ = log_{ {2}^{2a} }( {2}^{b} ) \\ = \frac{b}{2a} log_{2}(2) \\ = \frac{b}{2a} [/tex]