Tentukan akar akar dari persamaan berikut A.4x²=25 B.2x(x-5)=0

A.
[tex]{4x}^{2} = 25 \\ \sqrt{ {4x}^{2} } = \sqrt{25} \\ 2x = 5 \\ x = \frac{5}{2} \\ x = 2 \ \frac{1}{2} [/tex]
B.
[tex]2x(x - 5) = 0 \\ x - 5 = - 2x \\ - 5 = - 2x - x \\ 5 = 2x + x \\ 5 = 3x \\ x = \frac{5}{3} [/tex]
Semoga membantuu ^__^ Like yaa jadikan terbaik

A) 4x² = 25
     4x² - 25 = 0
     (2x - 5) (2x + 5) = 0

      2x - 5 = 0
      2x = 5
        x = 5/2

      2x + 5 = 0
      2x = - 5
        x = -5/2

B) 2x(x - 5) = 0
     2x = 0
       x = 0

      x - 5 = 0
      x = 5