Sederhanakanlah 27^2/3 +3√64-(16)^-3-4=

[tex] {27}^{ \frac{2}{3} } + 3 \sqrt{64} - {16}^{ - 3} - 4 \\ = {( {3}^{3}) }^{ \frac{2}{3} } + 3(8) - \frac{1}{4096} - 4 \\ = 9 + 24 - \frac{1}{4096} - 4 \\ = 29 - \frac{1}{4096} [/tex]
maaf gantung jawabnya, agak ribet kalo angka nya gede banget
maaf ya