(4x+5y)(cx+dy) = ex^2+23xy+6y^2 tentukan nilai c, d, dan e

◾ Materi : Persamaan Kuadrat
◾ Sub materi : PK
◾ Mapel : Matematika
◾ Keyword :

Jawab :
(4x+5y)(cx + dy) = ex² + 23xy + 6y²
4cx²+4dxy+5cxy+5dy² = ex²+23xy+6y²
5cx² + xy(4d+5c)+5dy² = ex²+23xy+6y²

*5d = 6
d = 6/5

*4d+5c = 23
4(6/5) + 5c = 23
24/5 + 5c = 23
5c = 23 - 24/5
c = 115/5 - 24/5
c = 91/5

*5c = e
5(91/5) = e
91 = e

Jadi, c = 91/5 , d = 6/5 , e = 91

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-vin