[tex] \frac{1}{256} + \frac{1}{128} + \frac{1}{64} + \frac{1}{32} + .......[/tex] tentukan s6 dari deret bilangan di atas

◾ Materi : Barisan dan Deret
◾ Sub materi : Deret
◾ Mapel : Matematika
◾ Keyword : Deret Geometri

Jawab :
r = u2/u1 = 1/128/1/256 = 1/128 x 256/1 = 2
r>1
a = 1/256

S6 = a(r^n - 1)/r-1
S6 = 1/256 (2^6 - 1)/ (2-1)
S6 = 1/256 (64 - 1)/1
S6 = 1/256 (63)
S6 = 63/256


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-vin