Koordinat titik balik grafik fungsi kuadrat y=2x2 -8x - 10
Matematika
bagussomantri8213
Pertanyaan
Koordinat titik balik grafik fungsi kuadrat y=2x2 -8x - 10
1 Jawaban
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1. Jawaban aikyutala03
a = 2, b = -8, c = -10
Koordinat titik balik = (-b/2a , f(-b/2a))
= (8/4, f(8/4))
= (2 , f(2))
= (2,2·2²-8·2-10)
= (2,8-16-10)
= (2,-18)